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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Nested loops
At 2004-11-13 11:53 +0000, Peter Bradley wrote:
The problem is to create a list of invoices in a format something like this (all simplified as much as I can): Yes, nested "for-each" loops would do the trick simply if you don't have to deal with duplicates and determine only the unique ones from those. Now, I take the point I learnt last week that this is probably best done using <xsl:apply-templates>, Sure, that works too, a writer's choice of pull or push depends on how granular you want your stylesheet for later specialization, or how you want to use the template rules for other contexts. but how can I just pick the node set that has the correct invoice number? That is, I need to do something like: Process "/database/invoice/invoice_rec" * print the contents
* apply the invoice_total template for the node sharing the invoice number
Do this for each invoice_rec. Either pull: <xsl:for-each select="/database/invoice/invoice_rec">
...print the contents...
<xsl:for-each select="../../invoice_line/
invoice_line_rec[invoiceNumber=current()/invoiceNumber]">
...print the line...
</xsl:for-each>
<xsl:for-each select="../../invoice_line/
invoice_total[invoiceNumber=current()/invoiceNumber]">
...print total...
</xsl:for-each>
</xsl:for_each>Or push: <xsl:template match="/">
<xsl:apply-templates select="/database/invoice/invoice_rec"/>
</xsl:template>
<xsl:template match="invoice_rec">
...print the contents...
<xsl:apply-templates select="../../invoice_line/
invoice_line_rec[invoiceNumber=current()/invoiceNumber]"/>
<xsl:apply-templates select="../../invoice_line/
invoice_total[invoiceNumber=current()/invoiceNumber]"/>
</xsl:template>
<xsl:template match="invoice_line_rec">
...print the line...
</xsl:template>
<xsl:template match="invoice_total">
...print the total...
</xsl:template>I've tried all sorts of things including predicates and variables, but I just can't seen to find a valid XPath expression that gives me the node set I need. When you walk away from the current node in the evaluation of an XPath expression, the current() function can be used to "jump back" to where you started from the middle of the expression. The above assumes you aren't having to deal with duplicates. Put your focus on each invoice record and then address relatively from that record to all of the lines and the total whose reference is equal to the record you ware dealing with. You can also do it with keys: <xsl:key name="recs" match="invoice_rec" use="'all'"/> <xsl:key name="lines" match="invoice_line" use="invoiceNumber"/> <xsl:key name="totals" match="invoice_total" use="invoiceNumber"/> <xsl:template match="/">
<xsl:for-each select="key(recs,'all')">
...do contents...
<xsl:for-each select="key(lines,invoiceNumber)">
...do line...
</xsl:for-each>
<xsl:for-each select="key(totals,invoiceNumber)">
...do total...
</xsl:for-each>
</xsl:for-each>
</xsl:template>I hope this helps. It is untested since you didn't give any data to play with. ............................ Ken -- World-wide on-site corporate, govt. & user group XML/XSL training. G. Ken Holman mailto:gkholman@xxxxxxxxxxxxxxxxxxxx Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/ Box 266, Kars, Ontario CANADA K0A-2E0 +1(613)489-0999 (F:-0995) Male Breast Cancer Awareness http://www.CraneSoftwrights.com/s/bc Legal business disclaimers: http://www.CraneSoftwrights.com/legal
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