RE: RE: [Bu posta banka disindan gelmekte olup gerekt

Hi,

Rewrite your keys to

  <xsl:key name="categorise" match="value[C]" use="C"/>
  <xsl:key name="dkey" match="value[v1]" use="concat(../../C, ' ', v1)"/>

and

  <xsl:for-each select="value[generate-id() = generate-id(key('categorise',
C))]">
    <xsl:variable name="C" select="C"/>
    <xsl:for-each select="../value/B/value[generate-id() =
generate-id(key('dkey', concat($C, ' ', v1)))]">
      <xsl:variable name="miktar" select="sum(key('dkey', concat($C, ' ',
v1))/v2)"/>
      <fo:table-row>
        <fo:table-cell>
          <fo:block text-align="left" font-size="8pt" >
            <xsl:value-of select='format-number($miktar, "###,###.00")'/>
          </fo:block>
        </fo:table-cell>
      </fo:table-row>
    </xsl:for-each>
  </xsl:for-each>

I removed the ZZZ variable and mytemplate template call to make the grouping
clearer.

Cheers,

Jarno

> -----Original Message-----
> From: ext Osman Ginar Eren [mailto:Cinar.Eren@xxxxxxxxxxxxx]
> Sent: 19 November, 2004 09:21
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE: [xsl] RE: [Bu posta banka disindan gelmekte olup
> gerektiginde teyit alinmalidir.] - [xsl] find the sum over
> distinct nodes - Sender blacklisted
>
>
> hi,
>
> my problem seems to be related to multiple level grouping.
> there is a nice answer in your link. however my question is
> more complex; My second level grouping is not in the same
> level. My input data :
>  <value>
>
>          <B>
>              <key>aa</key>
>              <value>
>                  <v1>aa</v1>
>                  <v2>110</v2>
>              </value>
>          </B>
>          <B>
>              <key>bb</key>
>              <value>
>                  <v1>bb</v1>
>                  <v2>10</v2>
>              </value>
>          </B>
>          <B>
>              <key>cc</key>
>              <value>
>                  <v1>cc</v1>
>                  <v2>60</v2>
>              </value>
>          </B>
> 	   <C>002</C>
>  </value>
>
>  <value>
>         <B>
>              <key>bb</key>
>              <value>
>                  <v1>bb</v1>
>                  <v2>40</v2>
>              </value>
>          </B>
>          <B>
>              <key>cc</key>
>              <value>
>                  <v1>cc</v1>
>                  <v2>200</v2>
>              </value>
>          </B>
> 	   <C>002</C>
>  </value>
>
>  <value>
>          <B>
>              <key>dd</key>
>              <value>
>                  <v1>dd</v1>
>                  <v2>60</v2>
>              </value>
>          </B>
> 	   <C>001</C>
>  </value>
>
> my keys:
> <xsl:key name="categorise" match="value" use="C"/>
> <xsl:key name="dkey" match="value" use="v1"/>
>
> two groupings are as follows:
> first group according to C values of 'value' elements:
> <xsl:for-each select="value[generate-id()=
> generate-id(key('categorise',C)[1])]">
>      	<xsl:call-template name="mytemplate">
>       		<xsl:with-param name="ZZZ" select="$ZZZ" />
>      	</xsl:call-template>
>     </xsl:for-each>
>
> in my template:
> >   <xsl:for-each select="$ZZZ/B/value[generate-id(.) =
> > generate-id(key('dkey', v1))]">
> >     <xsl:variable name="miktar" select="sum(key('dkey',
> > v1)/v2)"/>
> >     <fo:table-row>
> >       <fo:table-cell>
> >         <fo:block text-align="left" font-size="8pt" >
> >           <xsl:value-of select='format-number($miktar,
> > "###,###.00")'/>
> >         </fo:block>
> >       </fo:table-cell>
> >     </fo:table-row>
> >   </xsl:for-each>
>
> so how can i move the first key value into the second one as
> it is given in the link below?(the two keys are in different
> levels in the XML)
>
> i am not sure if i could tell my problem, if it is not enough
> i can go deeper.
>
> thanks in advance.
> best regards...
>
>
> -----Original Message-----
> From: JBryant@xxxxxxxxx [mailto:JBryant@xxxxxxxxx]
> Sent: Thursday, November 18, 2004 7:09 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE: [xsl] RE: [Bu posta banka disindan gelmekte olup
> gerektiginde teyit alinmalidir.] - [xsl] find the sum over distinct
> nodes - Sender blacklisted
>
>
> I found that Dave Pawson's FAQ was also very helpful when I
> had to solve
> the flat-to-structured problem. The portion of the FAQ that
> deals with
> turning flat documents into structured documents is at
> http://www.dpawson.co.uk/xsl/sect2/flatfile.html
>
> My thanks to Jeni and Dave for creating these resources and
> to everyone on
> the list for all the input.
>
> Jay Bryant
> Bryant Communication Services
>
>
>
>
> "Michael Kay" <mike@xxxxxxxxxxxx>
> 11/18/2004 10:55 AM
> Please respond to
> xsl-list@xxxxxxxxxxxxxxxxxxxxxx
>
>
> To
> <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
> cc
>
> Subject
> RE: [xsl] RE: [Bu posta banka disindan gelmekte olup
> gerektiginde teyit
> alinmalidir.] - [xsl] find the sum over distinct nodes - Sender
> blacklisted
>
>
>
>
>
>
> Last time Jarno showed you what to do, you did something
> different and
> then
> said it didn't work.
>
> Now you still say it doesn't work, but you're not telling us
> what you've
> done this time.
>
> Show a complete source document, a complete stylesheet, the
> output you are
> getting, and the output that you want.
>
> It's going to be difficult for you to use Jarno's code
> correctly unless
> you
> study it enough to understand it. Reading Jeni's XSLT
> grouping pages will
> help greatly: http://www.jenitennison.com/xslt/grouping
>
> Michael Kay
> http://www.saxonica.com/