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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: how select all siblings?
Hardy,
Have you tried $section_legislators/legistor ?
Regards,
Kenneth
On Tue, 12 Oct 2004 14:42:17 -0400, Hardy Merrill
<hmerrill@xxxxxxxxxxxxxxxx> wrote:
> Here's a snippet from an XSL style sheet:
>
> <xsl:template name="display_section">
> <xsl:param name="section_legislators"/>
>
> <tr><td colspan="4">Count section_legislators:<xsl:value-of
> select="count($section_legislators)"/></td></tr>
> <xsl:variable name="sorted_legislators">
> <xsl:for-each select="$section_legislators">
> <xsl:sort select="district_type" />
> <xsl:sort select="district_no"
> data-type="number" />
> <xsl:sort select="legislator_active_date"
> data-type="number" order="descending" />
> <xsl:copy-of select="."/>
> </xsl:for-each>
> </xsl:variable>
> <tr><td colspan="4">Count sorted_legislators: <xsl:value-of
> select="count(msxsl:node-set($sorted_legislators))"/></td></tr>
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