Re: Xslt transform & grouping, Using the Muenchian Me

One more thing.
I also get all elements where filter=''. I need to get only
filter='food' and filter='drink', wheter element is child element
(Article) or parent element (Document), then I want to sort according
to title-attribute.

Thank you!


On Mon, 11 Oct 2004 10:10:32 +0200, row.filter <row.filter@xxxxxxxxx> wrote:
> ok.
> 
> Is this correct?
> I got some parent elements (Document) node hanging outside for some reason?
> 
> I would like also to filter on two attributes. It this correct
> (<xsl:copy-of select="@* | Article[@filter = 'food' or @filter=
> 'drink']"/>) ?
> 
> 
> <?xml version="1.0"?>
> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
> 
>  <xsl:template match="/">
>  <Documents>
>        <xsl:apply-templates select="Documents/Document[@filter = 'food' or
> @filter = '']">
>        <xsl:sort select="@title"/>
>        </xsl:apply-templates>
>  </Documents>
>  </xsl:template>
> 
>  <xsl:template match="/Documents/Document">
>    <xsl:copy>
>        <xsl:copy-of select="@* | Article[@filter = 'food']"/>
>    </xsl:copy>
>  </xsl:template>
> 
> </xsl:stylesheet>
> 
> 
> 
> 
> On Mon, 11 Oct 2004 09:19:16 +0200, Anton Triest <anton@xxxxxxxx> wrote:
> > row.filter wrote:
> >
> > >I get this exception:
> > >
> > >Exception Details: System.Xml.Xsl.XsltException: 'local-name()' is an
> > >invalid QName.
> > >
> > That's correct, you cannot use expressions in xsl:element name unless
> > you enclose them
> > in curly braces: <xsl:element name="{local-name()}">
> >
> > The next problem will be that every Document in the output will be
> > nested inside another
> > Document element, because of the <xsl:copy>.
> >
> > Infact, <xsl:copy> and <xsl:element name="{local-name()}"> do the same
> > thing so you
> > only need one of them (or use just <Document> instead).
> >
> > The code will also add multiple Document elements at the root level,
> > making it invalid XML
> > (an XML document should always have one root element). To ensure that
> > the output has
> > one root node, add <Documents> to the template match="/" (or, if you
> > prefer, use
> > match="/Documents" and then <xsl:copy>).
> >
> > HTH,
> > Anton
> >
> >
> >
> > >On Sun, 10 Oct 2004 11:27:20 -0700, M. David Peterson
> > ><m.david@xxxxxxxxxx> wrote:
> > >
> > >
> > >>I'm not sure if using keys is necessary as it seems they are already grouped
> > >>using the document order and hierarchy.  Either way, to ensure that they are
> > >>processed numerically if and only if the @filter attribute equals food or has no
> > >>value and then further more only include Article elements within each Document
> > >>structure that contain the @filter equal to food then your problem is pretty
> > >>simple...
> > >>
> > >><?xml version="1.0"?>
> > >><xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
> > >><xsl:template match="/">
> > >>  <xsl:apply-templates select="Documents/Document[@filter = 'food' or @filter =
> > >>'']">
> > >>    <xsl:sort select="@title"/>
> > >>  </xsl:apply-templates>
> > >>  </xsl:template>
> > >>  <xsl:template match="Document">
> > >>    <xsl:copy>
> > >>      <xsl:element name="local-name()">
> > >>        <xsl:copy-of select="@* | Article[@filter = 'food']"/>
> > >>      </xsl:element>
> > >>    </xsl:copy>
> > >>  </xsl:template>
> > >></xsl:stylesheet>
> > >>
> > >>Produces this using your sample XML input:
> > >>
> > >><Document title="1" chapter="1" href="file1.xml" filter="food">
> > >>  <Article title="1.1" info="sub" filter="food"/>
> > >>  <Article title="1.2" info="main" filter="food"/>
> > >></Document>
> > >><Document title="3" chapter="3" href="file2.xml" filter=""/>
> > >>
> > >>If this is not the output you want maybe an example of what you want the output
> > >>to look like will help us help you further.
> > >>
> > >>Best of luck!
> > >>
> > >><M:D/>
> > >>
> > >>
> > >>
> > >>
> > >>row.filter wrote:
> > >>
> > >>
> > >>>Hi,
> > >>>
> > >>>I would like to group following, by attribute Title, and then filter
> > >>>by attribute filter="food". Title-attribute exists in both Document
> > >>>and Article elements.
> > >>>
> > >>>That is, groups should be created based on attribute Title in Document
> > >>>element, and filtered by attribute e.g. filter="food".
> > >>>
> > >>>Currently I am using grouping and filtering in following stylesheet.
> > >>>
> > >>>All other elements, where filter != "food" should be ignored.
> > >>>Filter is global parameter.
> > >>>
> > >>>Thank you!
> > >>>
> > >>>
> > >>>Some help on the way:
> > >>>
> > >>>XSL:
> > >>>
> > >>><?xml version='1.0' encoding='UTF-8'?>
> > >>>
> > >>><xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> > >>>
> > >>><xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
> > >>>
> > >>><xsl:key name="by-info" match="Article" use="@info"/>
> > >>>
> > >>><xsl:param name="filter" select="'food'"/>
> > >>>
> > >>><xsl:template match="Documents">
> > >>>      <Documents>
> > >>>              <xsl:for-each select="Document[@filter='' or
> > >>>@filter=$filter]/Article[generate-id()=generate-id(key('by-info',@info)[@filter=$filter])]">
> > >>>                      <Document name="{@info}">
> > >>>                              <xsl:copy-of select="key('by-info',@info)[@filter=$filter]"/>
> > >>>                      </Document>
> > >>>              </xsl:for-each>
> > >>>      </Documents>
> > >>></xsl:template>
> > >>>
> > >>></xsl:stylesheet>
> > >>>
> > >>>
> > >>>XML:
> > >>>
> > >>><Documents>
> > >>>      <Document title="1" chapter="1" href="file1.xml" filter="food">
> > >>>              <Article title="1.1" info="sub" filter="food"/>
> > >>>              <Article title="1.2" info="main" filter="food"/>
> > >>>      </Document>
> > >>>      <Document title="2" chapter="2" href="file2.xml" filter="drink">
> > >>>              <Article title="2.1" info="sub" filter="drink"/>
> > >>>              <Article title="2.2" info="main" filter="food"/>
> > >>>      </Document>
> > >>>      <Document title="3" chapter="3" href="file2.xml" filter="">
> > >>>              <Article title="3.1" info="sub" filter="drink"/>
> > >>>              <Article title="3.2" info="child" filter=""/>
> > >>>      </Document>
> > >>></Documents>
> >
> >
> 
> 
> --
> 
> [row.filter]
> 


-- 

[row.filter]