Re: position and grouping?
> So it seems when I use the "position()" test above, I am not just > testing the position of the name within the record, but (also?) the > name within a group of records. Can someone clarify this? beware foreign terminoligy as it leads to confusion (on my part at least) XSLT and XML don't have records. position() _never_ relates to the location of a node in a source tree. It always refers to a position in a current node list (or sequence in 2.0). That is if you select a node with self:: it always has position() =1 even if it's the 1001 child of some parent. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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