Re: how to store node in variable?

How do I store a reference to a node in a variable

or what am I doing wrong? Here is what I have (maybe oversimplified) :

<xsl:variable name="me">
  <xsl:choose>
    <xsl:when test="<some condition>">
      <xsl:copy-of select=".." />
    </xsl:when>
    <xsl:otherwise>
      <xsl:copy-of select="." />
    </xsl:otherwise>
  </xsl:choose>
</xsl:variable> <xsl:call-template name="<some template>">
  <xsl:with-param name="myid" select="$me/@id" />
</xsl:call-template>

The with-param is always throwing an error, expression should result in a node-set.

If I add msxsl:node-set around my selects in the variable definition I get cannot convert result tree fragment to node-set.

Alternatively, is there any way to explicitly set the context node without using for-each?

    <xsl:variable name="condition" select="<some condition>"/>
    <xsl:variable name="me" select="../self::*[$condition] |
                                    self::*[not($condition)]"/>

--
World-wide on-site corporate, govt. & user group XML/XSL training.
G. Ken Holman                 mailto:gkholman@xxxxxxxxxxxxxxxxxxxx
Crane Softwrights Ltd.          http://www.CraneSoftwrights.com/s/
Box 266, Kars, Ontario CANADA K0A-2E0    +1(613)489-0999 (F:-0995)
Male Breast Cancer Awareness  http://www.CraneSoftwrights.com/s/bc
Legal business disclaimers:  http://www.CraneSoftwrights.com/legal