Re: Re: [xslt transform & grouping] Using the Muenchia

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Subject: Re: Re: [xslt transform & grouping] Using the Muenchian Method?
From: Anton Triest <anton@xxxxxxxx>
Date: Thu, 07 Oct 2004 16:37:54 +0200

Michael PG wrote:

I have choosen to work with parameters, like:

   <xsl:param name="info" select="'food'"/>
How can I implement filtering for two keywords, that is display all that have either "food" or "drink".

You can pass a nodeset in the param, much like David's example:

   <xsl:param name="filter">
       <a>food</a>
       <a>drink</a>
   </xsl:param>

then you would need the possibility to pass a nodeset, and the nodeset extension to access it: [@filter=exsl:node-set($filter)/a]. Both depend on the processor - I don't know if and how this is possible in yours.

If you really cannot pass a nodeset, you could always build up a search string something like

<xsl:param name="filter" select="';food;drink;'"/>

and then use [contains($filter,concat(';',@filter,';'))]

Anton

Current Thread

Re: Re: [xslt transform & grouping] Using the Muenchian Method?, (continued)
- Michael PG - Thu, 07 Oct 2004 13:53:11 +0000
  - David Carlisle - Thu, 7 Oct 2004 15:02:03 +0100
- Michael PG - Thu, 07 Oct 2004 14:08:57 +0000
  - Anton Triest - Thu, 07 Oct 2004 16:37:54 +0200 <=
  - David Carlisle - Thu, 7 Oct 2004 15:57:09 +0100
    - David Carlisle - Thu, 7 Oct 2004 15:59:51 +0100

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