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RE: xsl attribute value

Subject: RE: xsl attribute value
From: <Jarno.Elovirta@xxxxxxxxx>
Date: Wed, 27 Oct 2004 11:25:36 +0300
xsl attribute value

>    <Group>
>        <GroupValue type='PO'>PO0005</GroupValue>
>    </Group>
>    <Group>
>        <GroupValue type='SUPPLIER'>Supplier One</GroupValue>
>    </Group>
> </Report>
> In the above XML exmple I am trying to generate the following
> output :-
> PO = PO0005
> SUPPLIER = Supplier One
> I am using the following xslt.
> <?xml version="1.0" ?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> <xsl:template match="/Report">
>     <xsl:for-each select="Group">
>         <xsl:value-of select="GroupValue[@type]" /> =

"GroupValue" selects a node-set of "GroupValue" child element nodes, "[@type]"
filters out those nodes that do not have a "type" attribute, and xsl:value-of
will extract the string value of the first node in document order.

>         <xsl:value-of select="GroupValue" /><br />

Here, again, xsl:value-of will give you the string value of the first
GroupValue element.

>     </xsl:for-each>
> </xsl:template>
> </xsl:stylesheet>
> This is generating the following output :-
> PO0005 = PO0005
> Supplier One = Supplier One
> Basically it is not printing the vlue of attribute 'type'.
> When I chnge the XSLT as follows :-
> <xsl:template match="/Report">
>     <xsl:for-each select="Group/GroupValue">
>         <xsl:value-of select="@type" /> =
>         <xsl:value-of select="." /><br />
>     </xsl:for-each>
> </xsl:template>
> Then it works.
> But my requirement is to print attribute value if the
> current node is <Group>.

I don't understand, how would the output differ from the output your solution
above already generates with the source you showed us?


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