Re: Re: [xslt transform & grouping] Using the Muenchia

<Documents>
  <Document id="0001" filter="">
      <Article title="Mr"/>
      <Article forename="John" filter="food"/>
      <Article surname="Smith" filter=""/>
  </Document>
  <Document id="0002" filter="food">
      <Article title="Dr"/>
      <Article forename="Amy" filter=""/>
      <Article surname="Jones" filter="food"/>
  </Document>
</Documents>

From: Anton Triest <anton@xxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: Re: [xslt transform & grouping] Using the Muenchian Method?
Date: Wed, 29 Sep 2004 22:34:01 +0200

Hi Michael,

Sorry, I was too quick in suggesting to add the filtering test to the grouping predicate:

<xsl:for-each select="Document/Article
  [count(.|key('by-info', @info)[1])=1 and (@filter='food')]">

That worked with my sample input, but more out of coincidence.
The filter test actually belongs in the next statement:

<xsl:template match="Documents">
<Documents>
<xsl:for-each select="Document/Article[count(.|key('by-info', @info)[1])=1]">
<Document name="{@info}">
<xsl:copy-of select="key('by-info', @info)[@filter='food']"/>
</Document>
</xsl:for-each>
</Documents>
</xsl:template>

Hope that helps better :)

Anton