RE: problem adding a new element to an XML document us

I think this code will work fine according to your requirement.

<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>

  <xsl:template match="/">
    <xsl:apply-templates/>
  </xsl:template>

  <xsl:template match="ROWSET">
    <xsl:element name="TABLE">
      <xsl:text>mytable</xsl:text>
    </xsl:element>
	<xsl:copy-of select="."/>
  </xsl:template>
</xsl:stylesheet>

Regds
--prateek--

Prateek Narang
Professional Services
Innodata Isogen
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R Block, DLF City, Phase-III
Gurgaon, Haryana - 122 002
Phone:  +(091) 124-2562801
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www.innodata-isogen.com


-----Original Message-----
From: Garry Cronin [mailto:garry.cronin@xxxxxxxxxx]
Sent: Thursday, September 23, 2004 8:23 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re:  problem adding a new element to an XML document using
xsl:element...

Thanks David. I used  your suggestion i.e.

<xsl:template match="ROWSET">
   <ROWSET>
   <TABLE>mytable</TABLE>
    <xsl:apply-templates/>
   </ROWSET>
  </xsl:template>

and it works a treat.

I notice I still have to include the <ROWSET> and </ROWSET> literals in
the stylesheet. Can't I simply instruct the stylesheet to output the
existing ROWSET elements unchanged, without having to repeat them in the
stylesheet. The current solution implies that I would have to manually
recontruct any attributes the ROWSET element might have in the input
XML?

- Garry

David Carlisle wrote:

>>Any ideas what I'm doing wrong?
>>
>>
>
>two things
>
>a) you want to put your table element before the result of applying
>templates to the input, but you have
>
>  <xsl:template match="ROWSET">
>   <xsl:element name="TABLE">
>      <xsl:text>mytable</xsl:text>
>      <xsl:apply-templates/>
>    </xsl:element>
>  </xsl:template>
>
>which applies templates )inside_ the table element so it puts
>everything inside the table so you want
>
>   <xsl:template match="ROWSET">
>   <ROWSET>
>   <xsl:element name="TABLE">
>      <xsl:text>mytable</xsl:text>
>    </xsl:element>
>    <xsl:apply-templates/>
>   </ROWSET>
>  </xsl:template>
>
>or equivalently
>
>   <xsl:template match="ROWSET">
>   <ROWSET>
>   <TABLE>mytable</TABLE>
>    <xsl:apply-templates/>
>   </ROWSET>
>  </xsl:template>
>
>then you are applying templates to the children of ROWSET but you have
>no templates matching those elements so you get the result of the
>default template, which just results in the character data and no
>element markup (compare with the result of a stylesheet that just has
>an empty xsl:stylesheet element and no template children).
>
>You could add a template for * that does the identity transform (copied

>from the XSLT spec or the archives of this list or the faq) but if you
>want the whole tree copied there is no need to use apply templates at
>all you can just copy the tree:
>
>
>   <xsl:template match="ROWSET">
>   <ROWSET>
>   <TABLE>mytable</TABLE>
>    <xsl:copy-of select="*"/>
>   </ROWSET>
>  </xsl:template>
>
>David
>
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