RE: Sorting and replacing content

> I have this structure where the content of tags <A> to <E>
> have to determine the order of tag-content <a> to <e>. The
> result needs to be as shown below.
>
> I can manage to make a stylesheet with an <xsl:if> for each
> <A> to <E> asking whether the number is 1, 2, 3, 4 or 5, but
> I am sure there must be a simpler way to do this. I can not
> use position() since the position af the tags can change in
> the structure.
>
> <Root>
> <a>10</a>
> <b>20</b>
> <c>30</c>
> <d>40</d>
> <e>50</e>
> ...
>
> ...
> <A>3</A>
> <B>5</B>
> <C>1</C>
> <D>2</D>
> <E>4</E>
> </Root>
>
> Result I need:
>
> <no>30</no> <!-- C = 1 has to be first with the value of c
> (which is 30) --> <no>40</no> <no>10</no> <no>50</no> <no>30</no>


How about:

<xsl:variable name="uppercase" select="'ABCDE'"/>
<xsl:variable name="lowercase" select="'abcde'"/>

<xsl:template match="Root">
  <xsl:apply-templates select="A|B|C|D|E">
    <xsl:sort select="." data-type="number"/>
  </xsl:apply-templates>
</xsl:template>

<xsl:template match="A|B|C|D|E">
  <xsl:apply-templates select="/Root/*[local-name() =
translate(local-name(current()), $uppercase, $lowercase)]"/>
</xsl:template>

<xsl:template match="a|b|c|d|e">
  <no><xsl:value-of select="."/></no>
</xsl:template>

This sorts the uppercase elements and then calls apply-templates for the
lowercase namesakes.  It produces this output:

<no>30</no><no>40</no><no>10</no><no>50</no><no>20</no>

The last <no> is different to your example output, but I'm guessing
that's a typo.

cheers
andrew