Subject: RE: XSLT Doctype and XHTML output
From: "Michael Kay" <mhk@xxxxxxxxx>
Date: Wed, 8 Sep 2004 22:41:30 +0100
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> I don't know where to add:
> "http://www.w3.org/TR/html4/strict.dtd" to the
> above.
Use the doctype-system attribute of xsl:output
>
>
> Second:
> I am now using the ADODB Stream method to stream the result of the
> transformation correctly and then perform an response.binarywrite.
> However, lets say I'm interested in XHTML results so I add
> the following
> namespace decleration to the stylesheet:
>
> xmlns="http://www.w3.org/1999/xhtml"
>
> The encoding I specified in the xsl:output gets lost is this normal?
This means that the stylesheet won't output a meta element specifying the
encoding, but it shouldn't affect the encoding actually used. The reason it
won't output a meta element is that it doesn't find an HTML head element to
contain it - an XHTML head element is a completely different animal.
>
> Third:
> This is illegal? (Doctype decleration in top-level node match)
>
> <xsl:template match="/">
> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
> "http://www.w3.org/TR/html4/loose.dtd"/>
>
Yes, totally illegal. Stylesheets have to be well-formed XML.
Michael Kay
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