|
[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Omit Data While Using Copy
The first thing I spotted was an un-closed element, the final "<hanvisning>". Eliminate or fix that in order to get an XML document. A document that isn't well-formed, isn't XML.
Next I noticed that your encoding attribute value was in lower case. It should read "UTF-8".
To get to the heart of your problem, when you don't specify a template to use in processing a node, the default template is applied. That built-in template copies the text value of an un-matched node to the output. In this case, the text value of <titel>. By adding a "no-op" template that matches <titel>, the output will be suppressed:
<xsl:template match="titel" />
The next thing I noticed was that your template matches "kapitel/hanvisning". The <hanvisning> element has no child elements.
I am a little puzzled as to why the <titel> element is being processed. It is not a child of <hanvisning>. I had always thought that the default template was applied when <xsl:apply-templates /> is used, but it seems that is incorrect. Perhaps one of those better acquainted with the XSL spec can explain it to us.
--
Charles Knell
cknell@xxxxxxxxxx - email
-----Original Message-----
From: Trevor Majic <majic87@xxxxxxxxxxx>
Sent: Wed, 11 Aug 2004 13:57:39 -0500
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Omit Data While Using Copy
How would I be able to display all of the data from the following xml file,
EXCEPT for the <titel> text? (see xml example below which is one of 1200)
<?xml version="1.0"?><?xml:stylesheet type='text/xsl' href='manual.xsl'?>
<kapitel><titel>Measures every 10 percussion hours</titel><text/><hanvisning
from="ID(SEUHS-SLAGVT-10-MATARE13)">Feeder</hanvisning><text/><hanvisning
from="ID(SEUHS-SLAGVT-10-BOM19)">Boom</hanvisning><text/><hanvisning></kapitel>
I can use xsl:copy and select=node() to display everything, but no matter
what I try, I can't seem to keep the <titel> from displaying. If I try to
just use match, I am only able to display "Feeder".
This is the basic xsl I was working from:
<?xml version='1.0' encoding='utf-8' ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="kapitel/hanvisning">
<xsl:copy>
<xsl:value-of select="node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
If you respond to this, please be fairly descriptive, as I am very new to
xsl.
Thanks in advance,
Trevor
_________________________________________________________________
Take charge with a pop-up guard built on patented Microsoft. SmartScreen
Technology.
http://join.msn.com/?pgmarket=en-ca&page=byoa/prem&xAPID=1994&DI=1034&SU=http://hotmail.com/enca&HL=Market_MSNIS_Taglines
Start enjoying all the benefits of MSN. Premium right now and get the
first two months FREE*.
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|

Cart








