Subject: Re: using traslate function to replace strings
From: kotes mog <kotesm@xxxxxxxxx>
Date: Fri, 13 Aug 2004 12:11:40 -0700 (PDT)
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Marina,
Thanks for the help. The "replace-string" template
available in FAQ has solved the problem.
Thanks
Kotes
--- Marina Cuello <cuello@xxxxxxxxxxxxxx> wrote:
> > <xsl:value-of
> select="concat($cutA,'dependency'.$cutB)"/>
>
> I'm sorry, it's "concat($cutA,'dependency',$cutB)"
>
> Marina
>
>
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