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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: Simple list -> Nested list based on attribute valu
You should post what you have so far... Quoting jhaines@xxxxxxxxxxxxxxxxxx: > I have an XML document of the form > > <doc> > <item header='true'>Section 1</item> > <item>Section 1.1</item> > <item>Section 1.2</item> > > <item header='true'>Section 2</item> > <item>Section 2.1</item> > <item>Section 2.2</item> > </doc> > > that I want to transform to the following: > > <doc> > <section title="Section 1"> > <item>Section 1.1</item> > <item>Section 1.2</item> > </section> > > <section title="Section 2"> > <item>Section 2.1</item> > <item>Section 2.2</item> > </section> > </doc> > > I was able to match the @header <item>s with the rule 'item[@header = > "true"]' but couldn't work out a predicate to match "all subsequent > <item>s up until the next @header <item>". > > Jason > > > > Any information in this communication is confidential and may be privileged > or otherwise protected from disclosure without our consent. If you are not > the intended recipient, you are not authorised to and must not disclose, > copy, distribute, or retain this message or any part of it. You are requested > to please telephone or email the sender and delete this message and any > attachment from your system. > > Due to the electronic nature of e-mail, there is a risk that the information > contained in this message has been modified. Consequently we can accept no > responsibility or liability as to the completeness or accuracy of the > information. > > A-03-03-E > > O SAPO ja esta livre de vmrus com a Panda Software, fique vocj tambim! Clique em: http://antivirus.sapo.pt
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