Re: can you select name() of attributes?
The old line is commented out. I found that the old one would copy every attribute from $Doc1 if but one attribute of the same name exists in $Doc2. I don't think it should, what processor? You have changed [foo = bar] to [not(foo != bar)] these two expressions are not in general equivalent (eg if either foo or bar is a node set) but in your case both are the result of the name() function so they are strings, and for strings these expressions are equivalent. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star Internet. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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