Curious result of the position() function

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Subject: Curious result of the position() function
From: Roy <ra81@xxxxxxxxx>
Date: Thu, 29 Jul 2004 10:14:44 +0200

I believed that the position() function should give me the position number of the node in the node set. But it appears to not being the case. I don't understand the result of this function (I use saxon to process my xsl transformation). It numbers my row nodes 2 by 2. Can somebody explain me what I missed ?

Here are my test files :

test.xml
--------
<?xml version="1.0" encoding="iso-8859-1"?>
<document>
   <table>
      <row/>
      <row/>
      <row/>
      <row/>
      <row/>
   </table>
</document>

test.xsl -------- <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="ISO-8859-1" indent="yes"/> <xsl:template match="/"> <result> <xsl:apply-templates/> </result> </xsl:template> <xsl:template match="row"> <row-numbering> <xsl:text>Row number : </xsl:text> <xsl:number/> <xsl:text> ---------- Row position : </xsl:text> <xsl:value-of select="position()"/> </row-numbering> </xsl:template> </xsl:stylesheet>

result.xml
----------
<?xml version="1.0" encoding="ISO-8859-1"?>
<result>

<row-numbering>Row number : 1 ---------- Row position : 2</row-numbering>

<row-numbering>Row number : 2 ---------- Row position : 4</row-numbering>

<row-numbering>Row number : 3 ---------- Row position : 6</row-numbering>

<row-numbering>Row number : 4 ---------- Row position : 8</row-numbering>

<row-numbering>Row number : 5 ---------- Row position : 10</row-numbering>

</result>

Current Thread
Curious result of the position() function Roy - Thu, 29 Jul 2004 10:14:44 +0200 <= David Carlisle - Thu, 29 Jul 2004 10:20:18 +0100 <Possible follow-ups> Passin, Tom - Thu, 29 Jul 2004 10:51:34 -0400

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