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RE: Java namespace

Subject: RE: Java namespace
From: "Michael Kay" <mhk@xxxxxxxxx>
Date: Thu, 1 Jul 2004 15:25:20 +0100
java namespace
Questions about calling Java from XSLT are meaningless unless we know what
XSLT processor you are using. The mechanisms vary from one XSLT processor to
another.

Michael Kay 

> -----Original Message-----
> From: xptm@xxxxxxx [mailto:xptm@xxxxxxx] 
> Sent: 01 July 2004 14:10
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject:  Java namespace
> 
> First, let me tell i'm not a expertise in these areas, so 
> bear with me...
> 
> When i declare a namespace pointing to a Java class, is that 
> Java class treated
> as a Static class? Or does the XSL processor somehow 
> instatiates a object of
> that class?
> 
> I'm asking this cause i have this situation:
> 
> <?xml version="1.0" encoding="ISO8859-1" ?>
> <xsl:stylesheet version="2.0"
> 	xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>       	xmlns:gti = "SQLHelper" >
> 
> (...)
>             <xsl:element name="ResultSet">
>       		  <xsl:attribute name="sql"><xsl:value-of
> select="gti:AcertaSqlReservado($sql)"/></xsl:attribute>
>             </xsl:element>
> 
> This XSLT is called by a Java program
> 
> public class Tester{
>   public static void main(String[] args) {
>     try {
>       BufferedReader br = new BufferedReader(new InputStreamReader(new
> FileInputStream(xin+".xml")));
>       PrintWriter out = new PrintWriter(new 
> FileOutputStream(xout+".xml"));
>       try {
>         TransformerFactory xformFactory = 
> TransformerFactory.newInstance();
>         Source xsl = new StreamSource("Testes12.xsl");
>         Transformer stylesheet = xformFactory.newTransformer(xsl);
>         Source request = new StreamSource(br);
>         Result response = new StreamResult(out);
>         //stylesheet.setParameter("gui", "awt");
>         stylesheet.transform(request, response);
>       }
>       catch (TransformerException e) {
>         System.err.println(e);
>       }
>     }
>     catch (FileNotFoundException e) {
>       System.err.println(e);
>     }
>   }
>   }
> 
> This works OK, but if i change the XSL to
> 
> <?xml version="1.0" encoding="ISO8859-1" ?>
> <xsl:stylesheet version="2.0"
> 	xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>       	xmlns:gti = "Tester"   ---> the same Java class 
> that call the XSLT
> 
> i got a TransformerException.
> 
> But i don't understand why.
> 
> Thanks all.
> 
> 
> 
> 
> 
> 
> O SAPO já está livre de vírus com a Panda Software, fique você também!
> Clique em: http://antivirus.sapo.pt
> 
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Current Thread
  • Java namespace
    • xptm - Thu, 1 Jul 2004 14:10:01 +0100
      • Michael Kay - Thu, 1 Jul 2004 15:25:20 +0100 <=

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