Re: XSL resources - Flat to hierarchy - Common ancesto

Three questions in one mail:
1. Does anyone know of a public 'knowledgebase' type site where there
are lots of examples of solutions to different problems, classified in a
way which avoids spending hours trawling through threads?

2. Transforming 'flat' structures to hierarchies: I've adapted a stylesheet found in this list, for creating the hierarchy
of this:
<Menus>
<Menu MenuId="58" MenuName="LeftMenu"/>
<Menu MenuId="1" MenuParentId="58" MenuName="Home"/>
<Menu MenuId="60" MenuParentId="1" MenuName="About us/>
...etc
</Menus>

The xsl looks like this:
<xsl:template match="/">
	<xsl:apply-templates select="Menus"/>
</xsl:template>

<xsl:template match="Menus">
  <xsl:copy>
    <xsl:apply-templates select="Menu[not(@MenuParentId)]">
    </xsl:apply-templates>
  </xsl:copy>
</xsl:template>

<xsl:template match="Menu">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates select="../Menu[@MenuParentId =
current()/@MenuId]"/> </xsl:copy>
</xsl:template>

Question: is there any way of also adding the numbering (<xsl:number
level="multiple" format="1.1"/>) directly, or do I have to run the
output through a second stylesheet?

3. Given the hierarchical output from 2, I would like to extract all
nodes which are children of any of the ancestors of the node with a
given MenuId (including that node itself)
Expressed otherwise: the children, siblings, ancestors, uncles and
great-uncles, great-great-uncles (etc) of the given node.
Expressed otherwise: all Menus where MenuParentId IN (MenuIds of a given
node and all of its ancestors)

<xsl:template match="/Menus">
	<xsl:apply-templates select="Menu"/>
</xsl:template>

<xsl:template match="Menu" mode="MenuId">
<xsl:param name="MenuId"/>
... output what you want here ...
<xsl:apply-templates select="*[@MenuId = $MenuId]" mode="MenuId">
	<xsl:with-param name="MenuId" select="$MenuId"/>
</xsl:apply-templates>
</xsl:template>

<M:D/>
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Many thanks for any answers received

Ben Simkins