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Re: Positional predicates in pattern matching

Subject: Re: Positional predicates in pattern matching
From: David Carlisle <davidc@xxxxxxxxx>
Date: Fri, 2 Jul 2004 16:44:32 +0100
positional in xsl
your modes one and two are identical as the only difference is 
[true()]
but a filter of [true()] never does anything.

so to see why you get P2P3 $foo contains the second and third b child nodes
of a

so you apply templates to those two nodes.

match patterns are always evaluated against the source document not
against the node set used in the selection (you can't really use axis
notation to navigate around a node set) so

match="b[1]" matches any b that is the first b child of its parent
match="b[2]" matches any b that is the second b child of its parent
match="b[3]" matches any b that is the third b child of its parent


so when you apply templates to the $foo wiich is the second and third b
nodes the second and third templates fire and you get P1 from teh first
and P2 from the second.

then you do mode two which is identical except it writes out R2R3

david

-- 
The LaTeX Companion
  http://www.awprofessional.com/bookstore/product.asp?isbn=0201362996
  http://www.amazon.co.uk/exec/obidos/tg/detail/-/0201362996/202-7257897-0619804


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