Re:param problem

It seems there is some kind of conflict between the params in

<xsl:param name="sqlvars" select="'default'" />

and

   <func:function name="gti:facton">
     <xsl:param name="val"/>
     <func:result select="round($val div 14)"/>
   </func:function>

that are both define at the top element, but why? I've try to put both
declarations on different places but nothing works...


Citando xptm <xptm@xxxxxxx>:

> Hello:
>
> I have a xsl using exslt.org/functions
>
> <?xml version="1.0" encoding="ISO8859-1" ?>
> <xsl:stylesheet version="2.0"
>     xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>     xmlns:func="http://exslt.org/functions"
>     xmlns:gti="http://www.gtinformatica.pt">
>
>   <func:function name="gti:facton">
>     <xsl:param name="val"/>
>     <func:result select="round($val div 14)"/>
>   </func:function>
>
> </xsl:stylesheet>
>
> wich i'm importing into another
>
> <?xml version="1.0" encoding="ISO8859-1" ?>
> <xsl:transform version="2.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>   <xsl:output method="xml" version="1.0" encoding="iso-8859-1"
> indent="yes"/>
>   <!-- Funções -->
>   <xsl:include href="xfunctions.xsl" />
>   (...more stuff...)
>
> No i want to pass a parameter from a Java program to this XSLT, so i have
>
> <?xml version="1.0" encoding="ISO8859-1" ?>
> <xsl:transform version="2.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>   <xsl:output method="xml" version="1.0" encoding="iso-8859-1"
> indent="yes"/>
>
>  <xsl:param name="sqlvars" select="'default'" />
>
>   <!-- Funções -->
>   <xsl:include href="xfunctions.xsl" />
>   (...more stuff...)
>
> but i allways get this error:
>
> javax.xml.transform.TransformerException:
> javax.xml.transform.TransformerException: An EXSLT function cannot set
> more than one result!
>
> What is going on? I use Xalan Java 2.4.1
>
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