Fwd: [exslt] param problem

Hello:

Please forgive me for posting this in this list, but i got no answer from the
[exslt] list so i think maybe in here can help.


Hello:

I have a xsl using exslt.org/functions

<?xml version="1.0" encoding="ISO8859-1" ?>
<xsl:stylesheet version="2.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:func="http://exslt.org/functions"
    xmlns:gti="http://www.gtinformatica.pt">

  <func:function name="gti:facton">
    <xsl:param name="val"/>
    <func:result select="round($val div 14)"/>
  </func:function>

</xsl:stylesheet>

wich i'm importing into another

<?xml version="1.0" encoding="ISO8859-1" ?>
<xsl:transform version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" version="1.0" encoding="iso-8859-1"
indent="yes"/>
  <!-- Funções -->
  <xsl:include href="xfunctions.xsl" />
  (...more stuff...)

No i want to pass a parameter from a Java program to this XSLT, so i have

<?xml version="1.0" encoding="ISO8859-1" ?>
<xsl:transform version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" version="1.0" encoding="iso-8859-1"
indent="yes"/>

 <xsl:param name="sqlvars" select="'default'" />

  <!-- Funções -->
  <xsl:include href="xfunctions.xsl" />
  (...more stuff...)

but i allways get this error:

javax.xml.transform.TransformerException:
javax.xml.transform.TransformerException: An EXSLT function cannot set
more than one result!

What is going on? I use Xalan Java 2.4.1

_______________________________________________
exslt mailing list
list@xxxxxxxxx
http://www.exslt.org/list


----- Finalizar mensagem reenviada -----







O SAPO já está livre de vírus com a Panda Software, fique você também!
Clique em: http://antivirus.sapo.pt