Re: Add products of two recursive additions

If the structure is as you have described, then why not use sum()?

  <xsl:template match="/">
  <sums>
    c/data: <xsl:value-of select="sum(a/b/c/data)"/>
    d/data: <xsl:value-of select="sum(a/b/d/data)"/>
    all : <xsl:value-of select="sum(a/b/c/data | a/b/d/data)"/>
  </sums>
  </xsl:template>

If you do need the recursive addition then change the template to
return un-formated numbers, store them in variables and add them
together. Or, less efficiently, you could just pass all the nodes to
your existing functions like this:


<xsl:template match="/">
  <xsl:variable name="cd">
    <xsl:call-template name="orderlist.sum.edit">
      <xsl:with-param name="set-of-order" select="/a/b/d | /a/b/c"/>
    </xsl:call-template>
  </xsl:variable>
  <cd>
    <xsl:value-of select="$cd"/>
  </cd>
</xsl:template>

Josh

On Tue, 22 Jun 2004 12:16:46 +0100, James Steven
<jsteven@xxxxxxxxxxxxxxxxxxxxx> wrote:
> 
> Hello
> I have two recursive addition functions producing totals which I would like
> to add together.  How can I do this?
> 
> Eg To produce the first total I have used the xsl shown below:
> 
> <xsl:template match="a">
> <xsl:call-template name="orderlist.sum.edit">
> <xsl:with-param name="set-of-order" select="b/c"/>
> </xsl:call-template>
> </xsl:template>
> 
> The call-template above calls the template below to display the total for
> 'data':
> 
> <xsl:template name="orderlist.sum.edit">
> <xsl:param name="set-of-order"/>
> <xsl:variable name="sumorg">
> <xsl:call-template name="orderlist.sum">
> <xsl:with-param name="set-of-order" select="$set-of-order"/>
> </xsl:call-template>
> </xsl:variable>
> <xsl:value-of select='format-number($sumorg, "£###,###,##0.00")'/>
> </xsl:template>
> 
> <xsl:template name="orderlist.sum">
> <xsl:param name="set-of-order"/>
> <xsl:choose>
> <xsl:when test="$set-of-order">
> <xsl:variable name="first">
> <xsl:apply-templates select="$set-of-order[1]/data"/>
> </xsl:variable>
> <xsl:variable name="rest">
> <xsl:call-template name="orderlist.sum">
> <xsl:with-param name="set-of-order" select="$set-of-order[position() !=
> 1]"/>
> </xsl:call-template>
> </xsl:variable>
> <xsl:value-of select="$first + $rest"/>
> </xsl:when>
> <xsl:otherwise>0</xsl:otherwise>
> </xsl:choose>
> </xsl:template>
> 
> The second total is acquired in the same way.  An example of the xml I am
> using is also shown below:
> 
> <a>
> <b>
>  <c>
>    <data>1</data>
>  </c>
>   <c>
>    <data>3</data>
>  </c>
>  <d>
>    <data>1</data>
>  </d>
>  <d>
>   <data>5</data>
>  </d>
>  <d>
>   <data>2</data>
>  </d>
> </b>
> </a>
> 
> The two call-templates above refering to the recursive addition functions
> produce the totals for <data> in <c> as 5 and <d> as 7. How do I obtain 12
> as the total of both?
> 
> Thankyou very much for your help.
> 
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