RE: Output character references for all but one charac

Hi Andrew,

You seem to use xslt 2.0 but you instruct the processor to use version 1.0? 

HTH,
<prs/>

-----Original Message-----
From: Andrew Welch [mailto:ajwelch@xxxxxxxxxxxxxxx] 
Sent: Monday, June 21, 2004 11:20 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  Output character references for all but one character


Consider the following xml:

<node value="£">Hello&#160;World</node>

I have the problem where I need characters outside the ascii range to be
output as references, apart from the pound sign, which must remain as the
actual character.

The processor is Saxon 7.8 and is fixed.  I can't use d-o-e as the pound
sign is always an attribute value, and saxon 7.8 no longer supports d-o-e on
attributes in favour of character maps.  When I use the following
stylesheet, I get a '?' character instead of the the pound, I guess because
Saxon can't output the pound sign because it's not in the ascii range...  

<xsl:stylesheet version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:saxon="http://saxon.net.sf/"
  exclude-result-prefixes="saxon">

<xsl:output method="xhtml" encoding="ascii" omit-xml-declaration="yes"
use-character-maps="style"/>

<xsl:character-map name="style">
  <xsl:output-character character="£" string="&#163;"/> </xsl:character-map>

<xsl:template match="@*|node()">
  <xsl:copy>
    <xsl:apply-templates select="@*|node()"/>
  </xsl:copy>
</xsl:template>

</xsl:stylesheet>

Outputs:

<node value="?">Hello&#160;World</node>

I'm really after an exact copy of the input: 

<node value="£">Hello&#160;World</node>

Any ideas?

cheers
andrew

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