Re: sum() applied to a product

You could use a recursive template that does your stuff
try this one..

 <?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:template match="a">
  <xsl:call-template name="add-b">
   <xsl:with-param name="initial" select="0"/>
   <xsl:with-param name="counter" select="1"/>
   <xsl:with-param name="b-nodes" select="count(b)"/>
  </xsl:call-template>
 </xsl:template>
 <xsl:template name ="add-b">
  <xsl:param name="initial"/>
  <xsl:param name="counter"/>
  <xsl:param name="b-nodes"/>
  <xsl:param name="value"
select="(b[position()=$counter]/c)*(b[position()=$counter]/d)"/>
  <xsl:param name="sum" select="$initial+$value"/>
  <xsl:choose>
   <xsl:when test="$counter &lt; $b-nodes">
    <xsl:call-template name="add-b">
     <xsl:with-param name="initial" select="$sum"/>
     <xsl:with-param name="counter" select="$counter+1"/>
     <xsl:with-param name="b-nodes" select="$b-nodes"/>
    </xsl:call-template>
   </xsl:when>
   <xsl:otherwise>
    <xsl:value-of select="$sum"/>
   </xsl:otherwise>
  </xsl:choose>
 </xsl:template>
</xsl:stylesheet>


Hope this helps
Vasu Ch..
----- Original Message ----- 
From: "Brian Chrisman" <brian.chrisman@xxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Wednesday, June 30, 2004 12:36 AM
Subject:  sum() applied to a product


> Uggg... I had some sloppy cut-paste issue in my last post... this is what
it should have been, with a real subject line.  Sorry...
>
> -----------------------
> Okay.. I told someone I could do this in a simple xpath expression
>
> <?xml version="1.0"?>
> <a>
>   <b>
>     <c>2</c>
>     <d>4</d>
>   </b>
>   <b>
>     <c>3</c>
>     <d>6</d>
>   </b>
> </a>
>
> Where the xpath was to return (2*4) + (3*6) = 26
> I made several attempts with xpath's sum() function (using 1.0) and
> couldn't get it.
> I couldn't even come up with an expression that I thought might work..
> even though I tried several which I was certain would fail (which did).
>
> Any ideas?
>
>
>
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