[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message]

RE: Simple XSL but having problems

Subject: RE: Simple XSL but having problems
From: Dylan Barber <dylan.barber@xxxxxxxxxxxxx>
Date: Tue, 11 May 2004 11:30:13 -0500 (GMT-05:00)
simple xsl
Thanks guys none of that is working but after reading over the responses i think i have the right XSL it must be somewhere else in the code or XML (which is a remote feed)  I just thought the whole of XML maybe broke overnight. 

Thanks again!

-----Original Message-----
From: vsubramanian@xxxxxxxxxx
Sent: May 11, 2004 11:15 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: RE:  Simple XSL but having problems



If your desired output is :
<?xml version="1.0" encoding="UTF-8"?>
test1
                    ::
                    test2
                    ;;
            test3
                    ::
                    test4
                    ;;


Then try this
===================

<?xml version='1.0' encoding='utf-8' ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:template match="@*|*">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>
    <xsl:template match="a">
      
            <xsl:for-each select="b mod 2">
               
                    
                   <xsl:value-of select="c1"/>
                    ::
                    <xsl:value-of select="c2"/>
                    ;;
            </xsl:for-each>
       
    </xsl:template>    
</xsl:stylesheet>




-----Original Message-----
From: Dylan Barber [mailto:dylan.barber@xxxxxxxxxxxxx]
Sent: Tuesday, May 11, 2004 11:02 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject:  Simple XSL but having problems


Here is my xml layout

<a>
   <b>
       <c1>test1</c1>
       <c2>test2</c2>
   </b>
   <b>
   <b>
       <c1>test3</c1>
       <c2>test4</c2>
   </b>
</a>

and i want to show c1 and c2 so i have this 

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
	<xsl:template match="/">
			<xsl:for-each select="a/b">
				<xsl:value-of select="c1"/>
				::
				<xsl:value-of select="c2"/>
				;;
			</xsl:for-each>:|*|:
	</xsl:template>
</xsl:stylesheet>  


however all i get is :|*|:

what did i do wrong (please no rebukes I am trying to understand this and I
think this structure should work its easy enough)

Thanks !!!!!

----------------------------------------------------------------------------
-----------------
Dylan Barber                              :  AOL Messenger - dylanbarb
(CIW Professional, A+ Technician): MSN Messenger -
dylan.barber@xxxxxxxxxxxxx
Web Designer / Developer / Host
----------------------------------------------------------------------------
-----------------


Clip those URLs! - Short links are easier to remember.
http://clipurl.com



---------------------------------------------------------------------------------------------
Dylan Barber                              :  AOL Messenger - dylanbarb
(CIW Professional, A+ Technician): MSN Messenger - dylan.barber@xxxxxxxxxxxxx
Web Designer / Developer / Host
---------------------------------------------------------------------------------------------


Clip those URLs! - Short links are easier to remember.
http://clipurl.com

Current Thread

PURCHASE STYLUS STUDIO ONLINE TODAY!

Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced!

Buy Stylus Studio Now

Download The World's Best XML IDE!

Accelerate XML development with our award-winning XML IDE - Download a free trial today!

Don't miss another message! Subscribe to this list today.
Email
First Name
Last Name
Company
Subscribe in XML format
RSS 2.0
Atom 0.3
Site Map | Privacy Policy | Terms of Use | Trademarks
Free Stylus Studio XML Training:
W3C Member
Stylus Studio® and DataDirect XQuery ™are products from DataDirect Technologies, is a registered trademark of Progress Software Corporation, in the U.S. and other countries. © 2004-2013 All Rights Reserved.