Re: alphabetic counters - Solved

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Subject: Re: alphabetic counters - Solved
From: Nicholas Shanks <contact@xxxxxxxxxxxxxx>
Date: Tue, 11 May 2004 13:13:35 +0100

For the archives, here is the final solution:

XML: <food cite="bob1"/> <food cite="bob2"/> <food cite="jim"/> <citation id="bob1" author="Bob et al." year="2004" title="Fish & Chips" /> <citation id="bob2" author="Bob et al." year="2004" title="Bangers & Mash" /> <citation id="jim" author="Jim et al." year="2004" title="Toad in the Hole" />

XSLT: <xsl:key name="refs" match="citation" use="concat(@author,'+', @year)" />

<xsl:for-each select="food"> <xsl:value-of select="id(@cite)/@author" /> <xsl:text> </xsl:text> <xsl:value-of select="id(@cite)/@year" /> <xsl:variable name="cite" select="@cite" /> <xsl:if test="count(key('refs', concat(id(@cite)/@author,'+',id(@cite)/@year))) > 1"> <xsl:for-each select="key('refs', concat(id(@cite)/@author,'+',id(@cite)/@year))"> <xsl:if test="@id = $cite"><xsl:number value="position()" format="a" /></xsl:if> </xsl:for-each> </xsl:if> </xsl:for-each>

Output:
Bob et al. 2004a
Bob et al. 2004b
Jim et al. 2003


Thanks to all who helped with this!
- Nick.

Current Thread

Re: alphabetic counters, (continued)
- Passin, Tom - Mon, 10 May 2004 15:18:35 -0400
  - John-Mark Gurney - Mon, 10 May 2004 13:01:23 -0700

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Re: alphabetic counters, Nicholas Shanks	Thread	RE: alphabetic counters, Andreas L. Delmelle
RE: Slightly OT: Java XPointe, Mullee, John	Date	Re: problem: recursive templa, Jeni Tennison
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