RE: XSL-output for xml without parent node
I'm aware the Input XML Is in invalid format and that was one of the reason's i was curious if there was anyother way . --- Kenny Akridge <kenny@xxxxxxxxxxxxxxxxx> wrote: > The first problem is that your XML is invalid. You > need to have one root > node for the entire element. As soon as you fix > that, you will get 1 2 3 in > your output. > > Make your xml look something like this. You may > want to read some more XSLT > tutorials as well. > > <root> > <RESULT ID="1" NAME="te"/> > <RESULT ID="2" NAME="tes"/> > <RESULT ID="3" NAME="tess"/> > </root> > > -----Original Message----- > From: Bret [mailto:laker_66@xxxxxxxxx] > Sent: Tuesday, May 04, 2004 5:04 PM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: XSL-output for xml without parent > node > > Hi! > I have the following xml . > > <RESULT ID="1" NAME="te"/> > <RESULT ID="2" NAME="tes"/> > <RESULT ID="3" NAME="tess"/> > > > I have the following xsl > > <xsl:stylesheet version="1.0" > xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > xml:space="preserve"> > <xsl:template match="/"> > <html> > <body> > <xsl:for-each select="//RESULT"> > <xsl:value-of select="@ID"/> > </xsl:for-each> > </body> > </html> > </xsl:template> > </xsl:stylesheet> > > when i use the following xsl i'm not getting any > output . I'm guessing it has to > do with <xsl:for-each select="//RESULT"> . > > I do get output if i have only one record in the XML > file . > > Any help appreciated . > > Thanks!!!! > > > > > > __________________________________ > Do you Yahoo!? > Win a $20,000 Career Makeover at Yahoo! HotJobs > http://hotjobs.sweepstakes.yahoo.com/careermakeover > __________________________________ Do you Yahoo!? Win a $20,000 Career Makeover at Yahoo! HotJobs http://hotjobs.sweepstakes.yahoo.com/careermakeover
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