Cart
|
[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: Changing Attribute Value in all the ChildNodes at
 Hi Animesh,
Please try the XSL -
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0"
encoding="UTF-8" indent="yes"/>
<xsl:template match="node()">
<xsl:copy>
<xsl:if test="ancestor::csf">
<xsl:apply-templates select="@*[not(name() =
'href')]" mode="x"/>
<xsl:apply-templates select="@*[name() =
'href']" mode="y"/>
</xsl:if>
<xsl:if test="not(ancestor::csf)">
<xsl:apply-templates select="@*" mode="x"/>
</xsl:if>
<xsl:apply-templates />
</xsl:copy>
</xsl:template>
<xsl:template match="@*" mode="x">
<xsl:attribute name="{name()}">
<xsl:value-of select="." />
</xsl:attribute>
</xsl:template>
<xsl:template match="@*" mode="y">
<!-- blank template -->
</xsl:template>
</xsl:stylesheet>
This removes the attribure "href" from the subtree of
node "csf".
For e.g., when the XSL is applied to XML -
<?xml version="1.0" encoding="UTF-8"?>
<root>
<body>
<namespace>
<form>
<snip href="1" a="2" b="3">
<csf href="4" c="5" d="6">
<td href="7" e="8" f="9"> <table
href="10" g="11" h="12">
table1
</table>
</td>
</csf>
</snip>
</form>
</namespace>
</body>
<body>
<namespace>
<form>
<snip href="1" a="2" b="3">
<csf href="4" c="5" d="6">
<td href="7" e="8" f="9"> <table
href="10" g="11" h="12">
table2
</table>
</td>
</csf>
</snip>
</form>
</namespace>
</body>
</root>
it produces output ,
<?xml version="1.0" encoding="UTF-8"?>
<root>
<body>
<namespace>
<form>
<snip href="1" a="2" b="3">
<csf href="4" c="5" d="6">
<td e="8" f="9">
<table g="11" h="12">
table1
</table>
</td>
</csf>
</snip>
</form>
</namespace>
</body>
<body>
<namespace>
<form>
<snip href="1" a="2" b="3">
<csf href="4" c="5" d="6">
<td e="8" f="9">
<table g="11" h="12">
table2
</table>
</td>
</csf>
</snip>
</form>
</namespace>
</body>
</root>
Regards,
Mukul
--- Animesh Sharma <asharma@xxxxxxxxxxxxxxxx> wrote:
>
> Thanks for the suggestion.
>
> But the problem is I wanted to retain the other part
> of the original XML. It is something that I want to
> modify the property (Attribute) of sub tree while
> not touching the rest of Tree.
>
> Something like:
>
> <xsl:template
>
match="//body/namespace/form/snip/csf/td[position()=1]/table[position()=2]">
> <xsl:copy>
> <xsl:apply-templates
> select="@*[not(name()='href')]"/>
> <xsl:apply-templates select="*|text()"/>
> </xsl:copy>
> </xsl:template>
>
> 'Default Template
> <xsl:template match="*|text()|@*">
> <xsl:copy>
> <xsl:apply-templates select="*|text()|@*"/>
> </xsl:copy>
> </xsl:template>
>
> And this thing doesn't works. Don't know why?
> May be Default template might reintroduce the
> attribute removed by first template.
>
> Will changing priority of first template would be of
> any help?
>
> Thanks once again
> Animesh
>
>
> -----Original Message-----
> From: Andreas L. Delmelle
> [mailto:a_l.delmelle@xxxxxxxxxx]
> Sent: Thursday, May 27, 2004 9:40 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE: Changing Attribute Value in all
> the ChildNodes at any
> level down the current node.
>
>
> > -----Original Message-----
> > From: Animesh Sharma
> [mailto:asharma@xxxxxxxxxxxxxxxx]
> >
>
> Hi,
>
> > I have to remove a particular attribute (in
> following example it
> > is "href") from all the ChildNodes of the
> particular node.
> >
> > I tried to write template something as follows:
> >
> > <xsl:template
> >
>
match="//body/namespace/form/snip/csf/td[position()=1]/table[posit
> > ion()=2]">
> > <xsl:apply-templates select="@*"/>
> > <xsl:attribute name="href"/>
>
> AFAIK, xsl:attribute is not a self-closing element,
> so if you really want to
> create an empty href attribute, at least there
> should be
> <xsl:attribute name="href"></xsl:attribute>
>
> Although, I'm not sure whether this will work...
> (haven't needed or tested
> anything like it)
>
> If you just want to omit the href attribute from
> being output, you have two
> options:
>
> For both: remove the 'empty' xsl:attribute element
> you specified above. It
> serves no purpose.
>
> 1. replace <xsl:apply-templates select="@*" /> by
> <xsl:apply-templates
> select="@*[not(name()='href')]" />
>
> 2. keep the current form of the apply-templates
> instruction, and define a
> null template matching @href, like <xsl:template
> match="@href" />
>
>
> Hope this helps!
>
> Greetz,
>
> Andreas
>
__________________________________
Do you Yahoo!?
Friends. Fun. Try the all-new Yahoo! Messenger.
http://messenger.yahoo.com/
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! 
Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|
