RE: XSLT Disable-Output-Escaping Not Working
Hi Shelli, You do not need to use the d-o-e, since in fact, as it was pointed out, doesn't do anything on attribute values. Your code should work fine without it. However, you need to set the output to html. To demonstrate, I have created the following XML: <root> <title>This & That</title> </root> and XSLT: <xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html" omit-xml-declaration="yes"/> <xsl:template match="/"> <xsl:element name="img"> <xsl:attribute name="src">xxx</xsl:attribute> <xsl:attribute name="alt"> <xsl:value-of select="root/title"/> </xsl:attribute> </xsl:element> </xsl:template> </xsl:transform> which does output <img src="xxx" alt="This & That"> and that works fine in the browser. I tested on Xselerator 2.6. HTH, <prs/> http://www.pietsieg.com http://www.pietsieg.com/dotnetnuke -----Original Message----- From: Shelli D. Orton [mailto:shelli.orton@xxxxxxxxx] Sent: Thursday, May 13, 2004 11:29 AM To: XSL List Subject: XSLT Disable-Output-Escaping Not Working Hi, I'm fairly new to XLST and have come across this problem. I have a template that creates an image element as below: <xsl:element name="img"> <xsl:attribute name="src"> <xsl:choose> <xsl:when test="Content/Title/image"> <xsl:value-of select="Content/Title/image" /> </xsl:when> <xsl:otherwise> <xsl:value-of select="$defaultImage"/> </xsl:otherwise> </xsl:choose> </xsl:attribute> <xsl:attribute name="alt"> <xsl:value-of select="MetaData/title" disable-output-escaping="yes"/> </xsl:attribute> </xsl:element> When the value of MetaData/title is "This & That", the & is escaped resulting in a title of "This &amp; That" which the browser displays as "This & That". Shouldn't the result be "This & That" which the browser displays as "This & That"? I have used the disable-output-escaping attribute in many other places and it has always worked before. Thanks for any help. Shelli
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