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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] select name of element / deal with embedded for-each
 as a beginner, I try to transform an XML structure like this one : <SOURCES>
<SOURCE CODE="SOURCE_1">
<INDEX>
<INDEX_A>A1</INDEX_A>
<INDEX_B>B1</INDEX_B>
<INDEX_C>C1</INDEX_C>
</INDEX>
</SOURCE>
<SOURCE CODE="SOURCE_2">
<INDEX>
<INDEX_A>A2</INDEX_A>
<INDEX_B>B2</INDEX_B>
<INDEX_C>C2</INDEX_C>
</INDEX>
</SOURCE>into an HTML table : <html> <body> <table> <tr> <td>INDEX_A</td> <td>A1</td> <td>A2</td> </tr> <tr> <td>INDEX_B</td> <td>B1</td> <td>B2</td> </tr> <tr> <td>INDEX_C</td> <td>C1</td> <td>C2</td> </tr> </table> </body> </html> I have two difficulties : 1. How to select the name of an element (in my case : <INDEX_A> must become : <td>INDEX_A</td> ). 2. How to write the xslt in order to treat /at once/ EACH INDEX FOR EACH SOURCE. I have some difficulties because of the two xsl:for-each that must coexist. I have tried : <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html"/> <xsl:template match="/"> <html> <body> <table border="1"> <xsl:for-each select="/SOURCES/SOURCE[1]/INDEX/*"> <tr> <xsl:for-each select="/SOURCES/SOURCE"> <td> <xsl:value-of select="INDEX/*"/> </td> </xsl:for-each> </tr> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet> but the result : A1 A2 A1 A2 A1 A2 is, as you see and have guessed, bad......... Thanks a lot for your help. Xyan 
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