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RE: Retrieving the position of an ancestor in nested
Subject: RE: Retrieving the position of an ancestor in nested <xsl:for-each>
From: <Jarno.Elovirta@xxxxxxxxx>
Date: Tue, 4 May 2004 14:10:29 +0300
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Hi,
Use a variable to store the node position.
> <xsl:for-each select="Node">
> ...
<xsl:variable name="node-position" select="position()"/>
> <xsl:for-each select="SubNode">
Position of Node: <xsl:value-of select="$node-position"/>
Cheers,
Jarno - Suicide Commando: Face Of Death (InterSekt Edit By Tactical Sekt)
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