RE: Transforming XML to XSL-FO by XSLT in java

--- Jarno.Elovirta@xxxxxxxxx wrote:
> Xalan-J documentation has examples of this
>
<http://xml.apache.org/xalan-j/usagepatterns.html#basic>,
> did you look at them?
> 
> Cheers,
> 
> Jarno - Rotersand: Electronic World Transmission
> ([:SITD:] reconstruction)
> 

Hi Jarno,
   I wrote the code by using procedure given in above
site using java;

Java code follows;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;

import javax.xml.transform.Transformer;
import
javax.xml.transform.TransformerConfigurationException;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;

public class xml2fo
{
	public static void main(String[] args){ 
  
	try{
		TransformerFactory tFactory =
TransformerFactory.newInstance();
	
		Transformer transformer =
tFactory.newTransformer(new
StreamSource("Furniture.xsl"));
	
		transformer.transform(new
StreamSource("Furniture.xml"), new StreamResult(new
FileOutputStream("Furniture.fo")));
	
		
	   }
	catch(Exception e){
	
	}
  }
}

But it shows the error like this;
C:\xalan\samples\SimpleTransform>java xml2fo
[Error] Furniture.xsl:5:391: Document root element
"xsl:stylesheet", must mat
DOCTYPE root "xml".
[Error] Furniture.xsl:5:391: Element type
"xsl:stylesheet" must be declared.
[Error] Furniture.xsl:6:30: Element type "xsl:output"
must be declared.
[Error] Furniture.xsl:7:35: Element type
"xsl:variable" must be declared.

I am not able to find whether it is XSLT or Java
coding..

Regards
Arul


	
		
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