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Re: Dynamical work with child nodes

Subject: Re: Dynamical work with child nodes
From: Mike Trotman <mike.trotman@xxxxxxxxxxxxx>
Date: Tue, 06 Apr 2004 15:19:27 +0100
get row childnodes
Depends on what you want to do - lots of possibilities.

Within your template:
<xsl:template match='row'> <!-- or however you select your <row> elements -->
<xsl:apply-templates select='*'/> <!-- to exclude immediate child TEXT nodes - no select needed to include them -->
<!-- you need to have templates defined to match the respective child elements occurring -->
<!-- OR -->
<xsl:for-each select='*'> <!-- to explicitly process them - e.g. sorted on their names -->
<xsl:sort order='ascending' data-type='text' use='name()'/>
<!--
... whatever you want to do
... even
<xsl:if test='name() = 'id'>....</xsl:if>
-->
</xsl:for-each>
<!-- OR to call specialised templates to just process the ones you want -->
<xsl:call-template name='magic-stuff'>
<xsl:with-param name='IDS' select='id'/>
</xsl:call-template>
</xsl:template>


Not sure if this helps or not (NSITHON).

Roland Juergens wrote:

Hi,

I have an XML file like this which contains results from a database query.
Is there a way to go dynamically through the subelements of my "row"
elements, because I want to use it for different queries.
So the subelements like "id" or "name" might change.

<root>
	<rowset>
		<row>
			<id>1</id>
			<name>bla</name>
		</row>
		<row>
			<id>2</id>
			<name>blabla</name>
		</row>

...(more <row> elements)...

	</rowset>
</root>


This is how the xsl-file looks like now


...
<xsl:for-each select="root/rowset/row">
...
	<xsl:value-of select="id"/>
...
	<xsl:value-of select="name"/>
...
</xsl:for-each>
...



What I imagine is the following :
I want to get the number of subelements of a "row" element, then iterate
over it to get the names, and then building it dynamical.
Is something like that possible ?


Roland Juergens



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