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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Getting the first and last nodes of a sorted nodeset
 Is it possible in XSLT to call a template one time where the 2
parameters are the first and last nodes in a sorted nodeset? A friend
of mine is trying to get a sorted list of dates and generate output for
all dates from the first to the last (whether they appear in the
original XML or not) via a named template which can take a start date
and a stop date and generate output for all the dates from start to
stop. I can't think of any way to do it.
<?xml-stylesheet type="text/xsl" href="test.xsl"?>
<root>
<test>
<nd>2003-12-31</nd>
<nd>2004-01-01</nd>
<nd>2004-01-02</nd>
<nd>2004-01-03</nd>
<nd>2004-01-04</nd>
<test>
<nd>2004-01-06</nd>
<nd>2004-01-03</nd>
<nd>2004-03-01</nd>
</test>
</test>
<test>
<nd>2004-02-08</nd>
<nd>2004-01-02</nd>
<nd>2004-02-03</nd>
<nd>2004-01-04</nd>
<nd>2004-02-08</nd>
</test>
</root>
<xsl:stylesheet xmlns:xsl='http://www.w3.org/1999/XSL/Transform'
version='1.0'>
<xsl:output method='html'/>
<xsl:key name='nd_key' match='nd' use='.'/>
<xsl:template match="/root">
<html>
<xsl:for-each
select="//nd[generate-id()=generate-id(key('nd_key',.)[1])]">
<xsl:sort select="."/>
<xsl:value-of select="."/><br/>
<xsl:if test="position()=last()">
<xsl:call-template name="test_template">
<!-- first element ?? What to replace select="." with ?? -->
<xsl:with-param name="b"><xsl:value-of
select="."/></xsl:with-param>
<!-- last element -->
<xsl:with-param name="c"><xsl:value-of
select="."/></xsl:with-param>
</xsl:call-template>
</xsl:if>
</xsl:for-each>
</html>
</xsl:template>
<xsl:template name="test_template">
<xsl:param name="b"></xsl:param>
<xsl:param name="c"></xsl:param>
<xsl:value-of select="$b" />
<xsl:value-of select="$c" />
</xsl:template>
</xsl:stylesheet>
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