Re: Read a parent node for particular chid using xsl
Thanks Jeni This will Solve my Problem.... Jeni Tennison <jeni@jenitenniso To: Shashi.Bhushan@xxxxxxxxx n.com> cc: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: Read a parent node for particular chid using xsl 03/24/2004 03:12 PM Please respond to xsl-list Hi Shashi, > I am not able to display the result as parent tile and child title > in single row. I think that you're probably having problems because the template for ReferencedBy does: <xsl:value-of select="//Result/@title" /> This will *always* give you the title of the first Result in your document because it's an absolute path: it starts at the root node for the document, finds all the title attributes of the Result elements, and then gives you the value of the first one. What you want is to get the title attribute of the Result element that's the parent of the current ReferencedBy element. To do that, use the parent axis: <xsl:value-of select="parent::Result/@title" /> A shorthand for getting the parent of a node is "..", so you could alternatively use: <xsl:value-of select="../@title" /> Note that you probably want to make the same change to the rest of the paths in that template. Cheers, Jeni --- Jeni Tennison http://www.jenitennison.com/ * * * * XANSA CONFIDENTIALITY NOTICE * * * * This message is intended only for the individual or entity to which it is addressed and may contain information that is privileged, confidential and exempt from disclosure under applicable law. If you are not the intended recipient, or the employee or agent responsible for delivering the message to the intended recipient, you are hereby notified that any dissemination, distribution or copying of this communication is strictly prohibited, and you are requested to please notify us immediately by telephone, and return the original message to us at the above address. Xansa North America 5555 San Felipe # 695 Houston, TX 77056 888-820-3030 www.xansa.com
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