RE: XPath to get value of xmlns attribute

xmlns "attributes" are represented as namespace nodes in the data model, not
as attribute nodes. You can find them using the namespace axis
(namespace::*). Note that this finds all the namespaces in scope, including
those declared on ancestor elements.

Michael Kay

# -----Original Message-----
# From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-
# list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Munna D
# Sent: 09 March 2004 13:20
# To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
# Subject:  XPath to get value of xmlns attribute
# 
# Hi,
# Say I have an xml document beginning as follows:
# <!--extract for example-->
# <?xml version="1.0" encoding="utf-8"?>
# <feed version="0.2" xmlns="http://purl.org/atom/ns#"
# xmlns:tt="http://www.tt.org/ns#">
# <!--end of extract-->
# 
# I want to make a list of all atttributes (including namespace declaration
# ones). However, both of the templates below fail to pick up the xmlns and
# xmlns:tt attributes:
# 	<xsl:template match='@*'>
# 		<xsl:value-of select="name()"/>
#                 ='<xsl:value-of select="."/>'
#         </xsl:template>
# 
# and
# 
# 	<xsl:template match="@*[starts-with(name(.),'xmlns')]" >
# 
# 		<xsl:value-of select="name()"/>
#                 ='<xsl:value-of select="."/>'
#         </xsl:template>
# 
# Can someone please tell me how I can get these values?
# 
# Thanks,
# Munna
# 
# 
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