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Re: Problem with xslt recursion

Subject: Re: Problem with xslt recursion
From: Roopesh Kumar <roopeshkumar_in@xxxxxxxxx>
Date: Wed, 11 Feb 2004 02:00:30 -0800 (PST)
verizon data services india
Thanks a lot for the solution..The outcome is very
precise to my requirement..I am amazed at the power of
xsl transformations after looking at the code..

will come back with moe doubts in future..


--- David Carlisle <davidc@xxxxxxxxx> wrote:
>  to address your doubt about why it is not enuf for
> me
>  to just use <xsl:copy-of select="Type/text()"/>
>  instead of recursion i have to further explain what
> i
>  am trying to do..
> See, it's always much easier to answer questions
> given sample input and
> desired output. You are correct that my one line
> xsl:copy can not add
> the  "_" between the items (In Xpath 2 this will be
> possible and the
> whole stylesheet below could be replaced by a single
> xsl:value-of)
> However you don't need recursion, just a small
> for-each loop over the
> elements
> <xsl:stylesheet
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
> version="1.0">
> <xsl:param name="x"/>
> <xsl:template match="Root">
>  <xsl:for-each
> select="Elements/Element[@name=$x]/R/Type">
>  <xsl:value-of select="/Root/*[name()=current()]"/>
>  <xsl:if test="position()!=last()">_</xsl:if>
>  </xsl:for-each>
> </xsl:template>
> </xsl:stylesheet>
> $ saxon concat.xml concat.xsl x=El1
> <?xml version="1.0" encoding="utf-8"?>R1_R2
> davidc@DCARLISLE /c/tmp
> $ saxon concat.xml concat.xsl x=El2
> <?xml version="1.0" encoding="utf-8"?>R1
> davidc@DCARLISLE /c/tmp
> $ saxon concat.xml concat.xsl x=El3
> <?xml version="1.0" encoding="utf-8"?>R1_R2_R3
> which matches your desired output I believe.
> -- 
> http://www.dcarlisle.demon.co.uk/matthew
>  XSL-List info and archive: 
> http://www.mulberrytech.com/xsl/xsl-list

Software Engineer 
Verizon Data Services India 


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