|
[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] RE: How Do I Select A Section of XML Based On A Code V
Something like this: <?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <xsl:for-each select="//VehInfo[descendant::UsageInfoCode = 'Work']"> <xsl:element name="VehInfo"> <xsl:element name="ModelYear"> <xsl:value-of select="ModelYear"/> </xsl:element> <xsl:element name="Model"> <xsl:value-of select="Model"/> </xsl:element> </xsl:element> </xsl:for-each> </xsl:template> </xsl:stylesheet> -----Original Message----- From: owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx [mailto:owner-xsl-list@xxxxxxxxxxxxxxxxxxxxxx] On Behalf Of Gary Fix Sent: Wednesday, February 25, 2004 10:17 AM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: How Do I Select A Section of XML Based On A Code Value Hi, I have an xml something like this: <VehInfo> <ModelYear>2004</ModelYear> <Model>Ford</Model> <UsageInfo> <UsageInfoCode>Work</UsageInfoCode> </UsageInfo> </VehInfo> <VehInfo> <ModelYear>1994</ModelYear> <Model>Toyota</Model> <UsageInfo> <UsageInfoCode>Pleasure</UsageInfoCode> </UsageInfo> </VehInfo> and want to transform this into xml using xsl, selecting the correct section based on the <UsageInfoCode> tag. For example, if I am to select using an "UsageInfoCode" of "Work", then I want the output xml to look like this: <VehInfo> <ModelYear>2004</ModelYear> <Model>Ford</Model> </VehInfo> Any help would be greatly appreciated! thanks....gary... XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
|
PURCHASE STYLUS STUDIO ONLINE TODAY!Purchasing Stylus Studio from our online shop is Easy, Secure and Value Priced! Download The World's Best XML IDE!Accelerate XML development with our award-winning XML IDE - Download a free trial today! Subscribe in XML format
|

Cart








