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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: sorting information from multiple files
Hello,
Its a little more complicated now as i managed to signififcantly reduce the amount of code by using nsindex. <xsl:for-each select="child::category"> <xsl:variable name="catnamemod" select="translate(name,' ','_')" /> <xsl:for-each select="document($nsindex/*[name()=$catnamemod])/root/child::*"> <xsl:if test="@topfive=true()"> <xsl:variable name="url" select="url" /> <li><a href="{$url}"><xsl:value-of select="title" /></a></li> </xsl:if> </xsl:for-each> </xsl:for-each> Basically in the second for-each there could be anything from 1-9 documents which are only known during the translation. The content form these files needs to be alphabetically ordered and i wasnt sure how to do it? nsindex refers to a node set of urls where the name of teh variables are equal to the different catnamemods... From: David Carlisle <davidc@xxxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: sorting information from multiple files Date: Thu, 15 Jan 2004 15:38:53 GMT _________________________________________________________________ It's fast, it's easy and it's free. Get MSN Messenger today! http://www.msn.co.uk/messenger XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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