Re: recursive addition

I'm really not doing very well here, am I?

I said *IF* it were a nested, rather than flat, file structure, I could do that.  As it is, I cannot.  

Perhaps the way to go is to write an xslt to convert from the flat file format to a nested one.

--Brendan

----- Original Message -----
From: "M. David Peterson" <m.david@xxxxxxxxxx>
Date: Wednesday, January 14, 2004 3:56 pm
Subject: Re:  recursive addition

> If all the folders within a root folder have the same 'id' (what 
> would be
> the point of having the 'id' attribute on the child folder 
> elements?) you
> could do this:
> 
> <xsl:value-of select="sum(//folder[@id = 'dir0']/@files)"/>
> 
> If they dont then this would do the trick:
> 
> <xsl:value-of select="sum(//folder[@id = 'dir0']/@files) + 
> sum(//folder[@id= 'dir0']//folder/@files)"/>
> 
> Im even more confused from your explanation than I was the first 
> time around
> but I think one of these will help you get to where you want to go.
> 
> Best of luck,
> 
> M.
> 
> ----- Original Message ----- 
> From: <annirack@xxxxxxx>
> To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
> Sent: Wednesday, January 14, 2004 3:58 PM
> Subject: Re:  recursive addition
> 
> 
> > > The semantics are most definitely unclear but im assuming that you
> > > know what
> > > you want to gain out of adding dir2 and dir3.
> >
> > I apparently didn't explain myself well at all.  Sorry about 
> that, here's
> another attempt:
> >
> > I have an XML file that represents a file system, and has a flat 
> filestructure.
> > All folder nodes are siblings and all file nodes are children of 
> a folder
> node.  To represent a folder being within another folder, a file 
> node can be
> a link to a folder node.
> >
> > Each folder node has an attribute that indicates how many files it
> contains.
> >
> > I want to know how many files are in all the subfolders of a 
> given folder.
> >
> > I don't know if this is even possible in xsl 1.0
> >
> > If it were not a flat file structure, it would seem easier... 
> since I
> could select all subfolders using  "root/folder[@id="some 
> id"]//folder" and
> some form of recursive algorithm could probably handle the rest.
> >
> > --Brendan
> >
> >
> >  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-
> list>
> 
> 
> XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
> 
> 


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list