RE: msxml stylesheet for displaying xml tree question

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Subject: RE: msxml stylesheet for displaying xml tree question
From: "Joe Fawcett" <joefawcett@xxxxxxxxxxx>
Date: Mon, 05 Jan 2004 13:53:26 +0000

From: "bryan" <bry@xxxxxxxxxx>
Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Subject:  msxml stylesheet for displaying xml tree question
Date: Mon, 5 Jan 2004 14:22:01 +0100


This is really sort of off-topic, I was thinking I might like to improve
my defaultss.xsl version I have, to do some of the things I want I need
to add some extension functions, one of which would be a function that
finds where the xml document that the xslt is displaying is located at
(remember that defaultss.xsl is a resource in the .dll) anyone have
suggestions on the best way to do this? Perhaps there's some hidden
objects/methods/properties exposed to the scripting environment for
extension functions in msxml that someone out there knows about?

Not sure what sort of things you need. I wrote a couple of trivial extensions for IE for looking at source code etc. They are both use a skeleton provided by Microsoft. They don't modify the default stylesheet though. They might give you some ideas... Run this reg file after copying the two files to the folders specified.

Windows Registry Editor Version 5.00

[HKEY_CURRENT_USER\Software\Microsoft\Internet Explorer\MenuExt\Show XML]
@="C:\\WINNT\\Web\\ShowXml.htm"
"contexts"=hex:01

[HKEY_CURRENT_USER\Software\Microsoft\Internet Explorer\MenuExt\Show XSL]
@="C:\\WINNT\\Web\\ShowXsl.htm"
"contexts"=hex:01

The two files are:
<!-- ShowXml.htm -->
<html>
<body>
<script language="JavaScript" defer>
<!--
// specific to context menu extensions
var win = external.menuArguments;
// the document object the user right-clicked on
var doc = win.document;
var sXml;
var sTitle;
// make sure our debugging window is a unique window
var wincounter = 0;

var mywin = window.open("about:blank", "source" + wincounter++, "toolbar=no,location=no,menubar=yes,status=yes,scrollbars=yes,resizable=yes"); while (mywin == null) { mywin = window.open("about:blank", "source" + wincounter++, "toolbar=no,location=no,menubar=yes,status=yes,scrollbars=yes,resizable=yes"); } // if (mywin == null)

var myDoc = mywin.document;

myDoc.open("text/plain");
if (doc.XMLDocument)
{
 sXml = doc.XMLDocument.xml;
 sTitle = "XML for: " + win.location.href;
}
else
{
 sXml = "No XML data found for document.";
 sTitle = "No XML for: " + win.location.href;
}
myDoc.write(sXml);
myDoc.close();
myDoc.title = sTitle;

// -->
</script>
</body>
</html>

AND

<!-- ShowXsl.htm -->
<html>
<body>
<script language="JavaScript" defer>
<!--
// specific to context menu extensions
var win = external.menuArguments;
// the document object the user right-clicked on
var doc = win.document;
var sXsl;
var sTitle;
// make sure our debugging window is a unique window
var wincounter = 0;

myDoc.open("text/plain");
if (doc.XSLDocument)
{
 sXsl = doc.XSLDocument.xml;
 sTitle = "XSL for: " + win.location.href;
}
else
{
 sXsl = "No stylesheet found for document.";
 sTitle = "No XSL for: " + win.location.href;
}
myDoc.write(sXsl);
myDoc.close();
myDoc.title = sTitle;


// -->
</script>
</body>
</html>

--

Joe

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Current Thread
RE: msxml stylesheet for displaying xml tree question Joe Fawcett - Mon, 5 Jan 2004 08:54:03 -0500 (EST) <= bryan - Mon, 5 Jan 2004 09:14:40 -0500 (EST) kakridge - Mon, 5 Jan 2004 11:13:07 -0500 (EST)

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