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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] xsl variable, param: need references to full tree
 as an example: "all title elements with level 0" should give me the element "title" with its childs commented as "element 1" a 2nd example: "all title elements with level 1" should give me the elements "title" with its childs commented as "element 2" and "element 3" <tablehead>
<title> <!-- this is element 1 -->
<value>Saldo letzter Abschluss</value>
<cssclass>head</cssclass>
<colwidth>250</colwidth>
<visibility>visible</visibility>
<layout>fixed</layout>
<subtitles>
<title> <!-- this is element 2 -->
<value>Soll</value>
<cssclass>head</cssclass>
<colwidth>125</colwidth>
<sortorder>no</sortorder>
</title>
<title> <!-- this is element 3 -->
<value>Haben</value>
<cssclass>head</cssclass>
<colwidth>125</colwidth>
<sortorder>no</sortorder>
</title>
</subtitles>
</title>
</tablehead>the following stylesheet do that (nearly) correct: - call to template: <xsl:call-template name="jumptolevel" > <!-- specify the level --> <xsl:with-param name="level" select="1" /> <!-- root titles --> <xsl:with-param name="elements" select="/tablehead/title" /> </xsl:call-template> - template itself: <xsl:template name="jumptolevel"> <xsl:param name="i" select="0" /> <xsl:param name="level" select="0" /> <xsl:param name="elements" /> <xsl:choose> <xsl:when test="$i < $level"> <xsl:call-template name="jumptolevel"> <xsl:with-param name="i" select="$i + 1" /> <xsl:with-param name="level" select="$level" /> <xsl:with-param name="elements" select="$elements/subtitles/title" /> </xsl:call-template> </xsl:when> <xsl:otherwise> <xsl:copy-of select="$elements" /> </xsl:otherwise> </xsl:choose> </xsl:template> the problem is, i need the result of the template "jumptolevel" as a reference in the whole tree. when i call the template as followed <xsl:variable name="test">
<xsl:call-template name="jumptolevel" >
<!-- specify the level -->
<xsl:with-param name="level" select="1" />
<!-- root titles -->
<xsl:with-param name="elements" select="/tablehead/title" />
</xsl:call-template>
</xsl:variable>
<xsl:value-of select="name($test/..)" />i want to have "subtitles" displayed! the result should give me also the parent nodes, how do i do that? or what i did wrong? thanks in advance (sorry, for my bad english, i'm swiss ;) jimmy XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list 
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