Re: knowing the position of certain node

You can just count the element on the preceding-sibling axis and add 1 to
that, for instance:
<xsl:value-of select="1 + count(row[field2='yes']/preceding-sibling::*)"/>

Best Regards,
 George
-------------------------------------------------------------
George Cristian Bina mailto:george@xxxxxxxxxxxxx
<oXygen/> XML Editor - http://www.oxygenxml.com/

----- Original Message -----
From: "Jaime A Stuardo Bahamondes" <jstuardo@xxxxxxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, January 06, 2004 3:50 PM
Subject:  knowing the position of certain node


> Hi all..
>
> I have this sample XML:
>
> <test>
>   <row>
>     <field1>this</field1>
>   </row>
>   <row>
>     <field1>is</field1>
>   </row>
>   <row>
>     <field1>a</field1>
>     <field2>yes</field2>
>   </row>
>   <row>
>     <field1>test</field1>
>   </row>
> </test>
>
>
> If I use <xsl:value-of select="row[field2 = 'yes']" /> I get all the third
"row" field values. How can I know the position of the found node? for
example, in that case, I want 3 to be printed on screen, something like
"position(row[field2 = 'yes'])"
>
> Thanks
> Jaime
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list
>


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list