Re: XPATH | union operator question

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Subject: Re: XPATH | union operator question
From: Marc Liyanage <liyanage@xxxxxxxxx>
Date: Sun, 21 Dec 2003 10:46:16 +0100

On 19.12.2003, at 17:40, G. Ken Holman wrote:

At 2003-12-19 16:05 +0100, christof.hoeke@xxxxxxx wrote:

In all four of the above, you are asking for the first in document order. XPath returns the nodes unordered but XSLT examines the returned nodes in document order.

I have a similar problem with this evaluation in document order:


  <things>
    <thing/>
    <thing xml:lang="de"/>
    <thing xml:lang="en"/>
  </things>

<value-of select="(thing[lang($mylang)] | thing)[1]"/>

What I tried with this was to get a specific thing with the requested language $mylang, and if no such element exists, to use the generic thing without the xml:lang attribute. Obviously this does not work, I always get the <thing/> first.

Is there an elegant solution to this?


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Current Thread

XPATH | union operator question
- christof . hoeke - Fri, 19 Dec 2003 10:05:53 -0500 (EST)
  - Michael Kay - Fri, 19 Dec 2003 10:55:09 -0500 (EST)
  - G. Ken Holman - Fri, 19 Dec 2003 11:40:49 -0500 (EST)
    - Marc Liyanage - Sun, 21 Dec 2003 04:46:27 -0500 (EST) <=
      - Dimitre Novatchev - Sun, 21 Dec 2003 05:59:08 -0500 (EST)
      - Andreas L. Delmelle - Sun, 21 Dec 2003 08:33:53 -0500 (EST)
      - Marc Liyanage - Sun, 21 Dec 2003 09:22:52 -0500 (EST)
      - Andreas L. Delmelle - Sun, 21 Dec 2003 09:53:14 -0500 (EST)

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Re: XPATH \| union operator qu, G. Ken Holman	Thread	Re: XPATH \| union operator qu, Dimitre Novatchev
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