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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: position() of parent node
Robert Ogden wrote:
...<xsl:for-each select="imageLink"> <xsl:if test="chapter[position() != 21]"> What I am getting at, is that I want to output all text links (easy enough), and all images for chapters unless the chapter is 21 (which happens also to be last, which I tried <xsl:if test="chapter[position() != last()]">)
You can try to count the previous siblings of the chapter. Of course, you'll have to navigate to the parent first: <xsl:if test="parent::chapter[count(previous-sibling::chapter)=21]"> or if you want the last (no following sibling chapter): <xsl:if test="parent::chapter[not(following-sibling::chapter)]"> J.Pietschmann XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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