Re: Can not convert #STRING to a NodeList! Error..
I guess, there is some problem with the way, you are using/accessing xsl:key definition. Can you please post the xsl:key definition, the source XML, and the desired output? I have experianced, that the error message "can not convert #STRING to a NodeList" comes, when a value of type *NodeList* was expected, and a *string value* is provided in its place.. Regards, Mukul --- arun prasath <arunwaits@xxxxxxxxxxx> wrote: > Hi, > In my XSL, > from the parent template I load a XML file using > document() function. and I > pass this as parameter to child templates. > <xsl:call-template name="main"> > <xsl:with-param name="labelsfile" > select="document('English.xml')"/> > </xsl:call-template> > > In my child templates, I am retrieving using > <xsl:param name="labelsfile"/> > > I also have declared a key(xsl:key) in the importing > xml file in my xsl. > <xsl:for-each select="$labelsfile"> > <xsl:value-of > select="key('label','ecollab.businessfollowedby')" > /> > </xsl:for-each> > > when I transform this using my java program, I get > the following exception. > Can not convert #STRING to a NodeList! > > I want to know why we get this error usually. > please help > regards > s.arun prasath > > _________________________________________________________________ > Make fun prints Click here to order. > http://www.kodakexpress.co.in Delivery > anywhere in India. > > > XSL-List info and archive: > http://www.mulberrytech.com/xsl/xsl-list > __________________________________ Do you Yahoo!? Protect your identity with Yahoo! Mail AddressGuard http://antispam.yahoo.com/whatsnewfree XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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