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Re: Can not convert #STRING to a NodeList! Error..

Subject: Re: Can not convert #STRING to a NodeList! Error..
From: Mukul Gandhi <mukulgw3@xxxxxxxxx>
Date: Sat, 8 Nov 2003 10:57:34 -0800 (PST)
Re:  Can not convert #STRING to a NodeList! Error..
I guess, there is some problem with the way, you are
using/accessing xsl:key definition. Can you please
post the xsl:key definition, the source XML, and the
desired output? 

I have experianced, that the error message "can not
convert #STRING to a NodeList" comes, when a value of
type *NodeList* was expected, and a *string value* is
provided in its place..

Regards,
Mukul

--- arun prasath <arunwaits@xxxxxxxxxxx> wrote:
> Hi,
> In my XSL,
> from the parent template I load a XML file using
> document() function. and I 
> pass this as parameter to child templates.
> <xsl:call-template name="main">
>    <xsl:with-param name="labelsfile"
> select="document('English.xml')"/>
> </xsl:call-template>
> 
> In my child templates, I am retrieving using
>     <xsl:param name="labelsfile"/>
> 
> I also have declared a key(xsl:key) in the importing
> xml file in my xsl.
>     <xsl:for-each select="$labelsfile">
>         <xsl:value-of
> select="key('label','ecollab.businessfollowedby')"
> />
>     </xsl:for-each>
> 
> when I transform this using my java program, I get
> the following exception.
> Can not convert #STRING to a NodeList!
> 
> I want to know why we get this error usually.
> please help
> regards
> s.arun prasath
> 
>
_________________________________________________________________
> Make fun prints Click here to order.
> http://www.kodakexpress.co.in  Delivery 
> anywhere in India.
> 
> 
>  XSL-List info and archive: 
> http://www.mulberrytech.com/xsl/xsl-list
> 


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