RE: Making XPath expressions out of variables

Hi,

> This is a theoretical bit of XSL code which I need a 
> practical version of:
> 
> All the variables are passed as parameters to the stylesheet.
> 
> <xsl:for-each select="//$record-type">
> 	<xsl:sort select="$sort-by" order="$sort-order" />
> 	<xsl:if test="$lh-operator $operand $rh-operator">
> 		<tr>
>  			<xsl:for-each select="*">
> 				<td><xsl:value-of select="." /></td>
> 			</xsl:for-each>
> 		</tr>
> 	</xsl:if>
> </xsl:for-each>
> 
> Any ideas? Is it possible? Or do I need to use this basic 
> construct multiple 
> times using <xsl:if> for each variable and the correct names 
> of nodes and 
> operands. (The number of permutations is massive!)

You can create a template

  <xsl:template name="comparison">
    <xsl:param name="operator"/>
    <xsl:param name="lh"/>
    <xsl:param name="rh"/>
    <xsl:choose>
      <xsl:when test="$operator '='">
        <xsl:value-of select="$lh = $rh"/>
      </xsl:when>
      ...
    </xsl:choose>
  </xsl:template>

that contains the operator functionality and use it with

    <xsl:variable name="result">
      <xsl:call-template name="comparison">
        <xsl:with-param name="operator" select="$operand"/>
        <xsl:with-param name="lh" select="$lh-operator"/>
        <xsl:with-param name="rh" select="$rh-operator"/>
      </xsl:call-template>
    </xsl:variable>
    <xsl:if test="$result = 'true'">
      ...

See FXSL <http://fxsl.sourceforge.net/>.

> Is there a way of selecting nodes which have the name 
> $some-variable using an 
> XPath expression?
> 
> e.g. <xsl:for-each select="//$some-variable">
> 
> would, in theory (though not in practice - I've tried it!), 
> select all the 
> nodes whose name is equal to whatever the value of $some-variable is.

  <xsl:for-each select="//*[local-name() = $some-variable]">

Cheers,

Jarno - Velvet Acid Christ: Futile (Resisted mix by Funker Vogt)

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