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Folks,
I have a very simple XML, XSL file and a very simple ASP file to perform the XSL Transformation on the XML file using the XSL file and providing it to any client browswer. I get the following error. NOTE: If I open the xml file (that is just from the client side) it works just fine! What am I missing??? ERROR --------- msxml3.dll error '80004005' The stylesheet does not contain a document element. The stylesheet may be empty, or it may not be a well-formed XML document. /test/vqtreport.asp, line 9
<DUMMY> </DUMMY> XSL FILE - dummy.xsl ------------ <?xml version='1.0'?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html" indent="yes"/> <xsl:template match="/">
<html>
<h1>Yahoooooooo</h1>
</html>
</xsl:template>
</xsl:stylesheet>_________________________________________________________________ Get McAfee virus scanning and cleaning of incoming attachments. Get Hotmail Extra Storage! http://join.msn.com/?PAGE=features/es XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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