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[XSL-LIST Mailing List Archive Home] [By Thread] [By Date] [Recent Entries] [Reply To This Message] Re: xsl:value-of select : how to make some tags printe
Hi Judith,
Taking hint from David Carlisle's answer, I have
written this XSL --
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0"
encoding="UTF-8" indent="yes"/>
<xsl:template match="/">
<xsl:apply-templates select="//text" />
</xsl:template>
<xsl:template match="//text">
<xsl:copy>
<xsl:apply-templates select="node()" />
</xsl:copy>
</xsl:template>
<xsl:template match="sw">
<xsl:value-of select="." />
</xsl:template>
<xsl:template match="sub">
<sub>
<xsl:value-of select="." />
</sub>
</xsl:template>
</xsl:stylesheet>
You may want to avoid the XPATH expression //text. I
have used it to illustrate the concept.
David, please correct me if I am wrong.
Regards,
Mukul
--- Judith Rog <Judith.Rog@xxxxx> wrote:
> Hi,
> Could anyone help me with the following?
>
> Suppose I have the following XML:
>
> <book>
> <title>My first book</title>
> <chapter>
> <nr>1</nr>
> <text> This is the <sw>content</sw> of my first
> book, where
> <sub>I</sub> would like to leave in the sub-tag, but
> leave out the
> sw-tag.</text>
> </chapter>
> </book>
>
> Is it possible to make an xsl statement that would
> print the content of
> the <text> tag and all sub tags (<xsl:value of
> select="text"/>) but then
> somehow leave the html formatting tags <sub> in the
> output? So:
> This is the content of my first book, where
> <sub>I</sub> would like to
> leave in the sub-tag, but leave out the sw-tag.
> instead of:
> This is the content of my first book, where I would
> like to leave in
> the sub-tag, but leave out the sw-tag.
>
> Thanks for your help.
> Judith
>
>
> XSL-List info and archive:
> http://www.mulberrytech.com/xsl/xsl-list
>
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